I ordered the wrong type BUT it still looks amazing!!
Discipline Zerozip Apr 2026
def _is_zero_filled(self, block): return all(byte == 0 for byte in block)
if block_type == 0: # Zero-filled block block_size = struct.unpack_from('H', compressed_data)[0] compressed_data = compressed_data[2:] decompressed_data.extend(bytes([0]) * block_size) else: # Non-zero-filled block block = self._decompress_non_zero_block(compressed_data) decompressed_data.extend(block) compressed_data = compressed_data[len(block):] discipline zerozip
return bytes(compressed_data)
return bytes(decompressed_data)
def _decompress_non_zero_block(self, compressed_block): decompressed_block = bytearray() i = 0 while i < len(compressed_block): count = struct.unpack_from('B', compressed_block, offset=i)[0] i += 1 byte = compressed_block[i] i += 1 decompressed_block.extend(bytes([byte]) * count) return bytes(decompressed_block) This implementation provides a basic example of the Discipline Zerozip algorithm. You may need to modify it to suit your specific use case. Discipline Zerozip offers a simple, yet efficient approach to lossless data compression. By leveraging zero-filled data blocks and RLE compression, it achieves competitive compression ratios with existing algorithms. The provided implementation demonstrates the algorithm's feasibility and can be used as a starting point for further development and optimization. def _is_zero_filled(self, block): return all(byte == 0 for
def _compress_zero_block(self, block): # Compress the zero-filled block using a simple header header = struct.pack('B', 0) # Block type (zero-filled) header += struct.pack('H', len(block)) # Block size return header By leveraging zero-filled data blocks and RLE compression,
import discipline_zerozip